LeetCode #326 PowerOfThree. Algorithm,알고리즘,LeetCode,Codefights,CodeSignal,코드파이트,코드시그널,예제,문제해결능력,example,c++,java,재귀,recursive,datastructure,techinterview,coding,코딩인터뷰,기술면접,연결리스트
Performance and Memory both good
LeetCode #237
Q.
Given an integer, write a function to determine if it is a power of three.
주어진 정수로, 3의 제곱 수인지 확인하는 함수를 만들어라.
e.g.
Example 1:
Input: 27
Output: true
Example 2:
Input: 0
Output: false
Example 3:
Input: 9
Output: true
Example 4:
Input: 45
Output: false
Follow up:
Could you do it without using any loop / recursion?
재귀나, 반복문 없이 가능함?
Process
// Process
//1. Input n
//2. Iterate till n >= 3
// 2.1. Check n / 3 is divisible
// 2.1.1. If not -> false
// 2.2. n /= 3
//3. Check if n == 1
// 3.1. return result
// 처리과정
//1. n 을 입력받는다.
//2. n >= 3 이면 반복한다.
// 2.1. n/3 이 나머지가 없는지 확인해서
// 2.1.1. 있으면 false
// 2.2. n 을 3으로 나눈다.
//3. n 이 1인지 확인한다.
// 3.1. 맞으면 true
// 3.2. 아니면 false
Code.. lemme see example code!!!
코드.. 예제코드를 보자!!!
class Solution {
public:
bool isPowerOfThree(int n) {
while (n >= 3) {
if (n % 3 != 0)
return false;
n /= 3;
}
return (n == 1);
}
};
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