LeetCode #206 ReverseLinkedList. Algorithm,알고리즘,LeetCode,Codefights,CodeSignal,코드파이트,코드시그널,예제,문제해결능력,example,c++,java,재귀,recursive,datastructure,techinterview,coding,코딩인터뷰,기술면접,연결리스트
다른거 풀다가 길 잘못들어서 한참 헤메다가 쉬운거라도 빨리 풀고 자려고 골랐는데 이것도 좀 걸림..
퍼포먼스는 최상, 메모리는 최하
Performance 100% , Memory 10%
LeetCode #206
Q.
Reverse a singly linked list.
단방향 싱글연결리스트를 뒤집어라
Example:
Input: 1->2->3->4->5->NULL
Output: 5->4->3->2->1->NULL
Follow up:
A linked list can be reversed either iteratively or recursively. Could you implement both?
반복이나 재귀로 되는데 둘다 해봐라
Process
// Process
//1. Input head node
//2. Make all int vector
//3. Iterate from end to the begin
// 3.1. Make reverse list
//4. Return reversedLinkedList
// 처리과정
//1. 헤드노드 입력받는다.
//2. 전체 노드들 정수 벡터를 만들어둔다.
//3. 만든 벡터 뒤에서부터 반복한다.
// 3.1. 노드들 채워준다
//4. 뒤집힌 노드 반환한다.
Code.. lemme see example code!!!
코드.. 예제코드를 보자!!!
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* reverseList(ListNode* head) {
vector<int> buffVector;
ListNode* buff = head;
while (head != 0) {
buffVector.push_back(head->val);
head = head->next;
}
head = buff;
int i = buffVector.size() - 1;
while (buff != 0) {
buff->val = buffVector[i--];
buff = buff->next;
}
return head;
}
};
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