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Algorithm/Leet Code

LeetCode #389 FindTheDifference. Algorithm,알고리즘,LeetCode,Codefights,CodeSignal,코드파이트,코드시그널,예제,문제해결능력,example,c++,java,재귀,recursive,datastructure,techinterview,coding,코딩인터뷰,기술면접,연결리..

LeetCode #389 FindTheDifference. Algorithm,알고리즘,LeetCode,Codefights,CodeSignal,코드파이트,코드시그널,예제,문제해결능력,example,c++,java,재귀,recursive,datastructure,techinterview,coding,코딩인터뷰,기술면접,연결리스트

 

 

 Performance and Memory both 99%%%

 

 

LeetCode #389

Q.

Given two strings s and t which consist of only lowercase letters.

String t is generated by random shuffling string s and then add one more letter at a random position.

Find the letter that was added in t.

 

 

Example:

Input:

s = "abcd"

t = "abcde"

 

Output: e Explanation: 'e' is the letter that was added.

 

 

Process

// Process
//1. Input string s , t
//2. Iterate s
// 2.1. Make dynamic s case
//3. Iterate t
// 3.1. Make dynamic t case
//4. Iterate dynamic cases
// 4.1. compare number
//5. Return result

 

 

// 처리과정

//1. 스트링 s, t 입력받는다.

//2. 스트링 s 반복한다.

// 2.1. s 동적 판 만든다.

//3. 스트링 t 반복한다.

// 3.1. t dynamic 판 만든다

//4. 동적판 반복한다

// 4.1. 다른수가 있는지 확인한다.

//5. 결과 반환한다.

 

 

Code.. lemme see example code!!!

코드.. 예제코드를 보자!!!

 

 

 

class Solution {
public:
    char findTheDifference(string s, string t) {
        char result;
        
        int dynamicS[26] = {0};
        int dynamicT[26] = {0};
        
        for (int i = 0; i < s.size(); ++i) {
            ++dynamicS[s[i] - 97];
        }
        
        for (int i = 0; i < t.size(); ++i) {
            ++dynamicT[t[i] - 97];
        }
        
        for (int i = 0; i < 26; ++i) {
            if (dynamicS[i] != dynamicT[i]) {
                result = i+97;
            }
        }
        
        return result;
    }
};

 

 

 

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