LeetCode #389 FindTheDifference. Algorithm,알고리즘,LeetCode,Codefights,CodeSignal,코드파이트,코드시그널,예제,문제해결능력,example,c++,java,재귀,recursive,datastructure,techinterview,coding,코딩인터뷰,기술면접,연결리스트
Performance and Memory both 99%%%
LeetCode #389
Q.
Given two strings s and t which consist of only lowercase letters.
String t is generated by random shuffling string s and then add one more letter at a random position.
Find the letter that was added in t.
Example:
Input:
s = "abcd"
t = "abcde"
Output: e Explanation: 'e' is the letter that was added.
Process
// Process
//1. Input string s , t
//2. Iterate s
// 2.1. Make dynamic s case
//3. Iterate t
// 3.1. Make dynamic t case
//4. Iterate dynamic cases
// 4.1. compare number
//5. Return result
// 처리과정
//1. 스트링 s, t 입력받는다.
//2. 스트링 s 반복한다.
// 2.1. s 동적 판 만든다.
//3. 스트링 t 반복한다.
// 3.1. t dynamic 판 만든다
//4. 동적판 반복한다
// 4.1. 다른수가 있는지 확인한다.
//5. 결과 반환한다.
Code.. lemme see example code!!!
코드.. 예제코드를 보자!!!
class Solution {
public:
char findTheDifference(string s, string t) {
char result;
int dynamicS[26] = {0};
int dynamicT[26] = {0};
for (int i = 0; i < s.size(); ++i) {
++dynamicS[s[i] - 97];
}
for (int i = 0; i < t.size(); ++i) {
++dynamicT[t[i] - 97];
}
for (int i = 0; i < 26; ++i) {
if (dynamicS[i] != dynamicT[i]) {
result = i+97;
}
}
return result;
}
};
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