LeetCode #237 DeleteNodeInALinkedList. Algorithm,알고리즘,LeetCode,Codefights,CodeSignal,코드파이트,코드시그널,예제,문제해결능력,example,c++,java,재귀,recursive,datastructure,techinterview,coding,코딩인터뷰,기술면접,연결리스트
문제 설명이 거지같았지만 쉬운 문제.. 노드의 포인터를 따라가서 주소값이 가리키는 값 자체를 바꿔준다.
Need to understand pointer
LeetCode #237
Q.
Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.
Given linked list -- head = [4,5,1,9], which looks like following:
싱글 연결리스트가 있는데, 함수에서는 노드 한개를 입력받는다. 입력 받은 노드를 연결리스트에서 삭제할 수 있는 방법을 찾아라.
e.g.
Example 1:
Input: head = [4,5,1,9], node = 5
Output: [4,1,9]
Explanation: You are given the second node with value 5, the linked list should become 4 -> 1 -> 9 after calling your function.
Example 2:
Input: head = [4,5,1,9], node = 1
Output: [4,5,9]
Explanation: You are given the third node with value 1, the linked list should become 4 -> 5 -> 9 after calling your function.
Note:
- The linked list will have at least two elements.
- All of the nodes' values will be unique.
- The given node will not be the tail and it will always be a valid node of the linked list.
- Do not return anything from your function.
메모:
- 연결리스트는 최소한 2개 이상 element 가 있다.
- 모든 노드는 중복 숫자가 없다.
- 입력받는 노드는 tail 이 아니고, 항상 유효한 노드다.
- 리턴값은 없다.
Process
// Process
//1. Input node will be deleted
//2. Replace value of inputNode adress to value of inputNode->next adress
//3. Finish
// 처리과정
//1. 지울 노드 입력받는다.
//2. 지울 노드의 주소값에 해당하는 값을, 지울 노드의 next 주소값에 해당하는 값으로 치환한다.
//3. 끝낸다.
Code.. lemme see example code!!!
코드.. 예제코드를 보자!!!
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
void deleteNode(ListNode* node) {
*node = *(node->next);
}
};
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