LeetCode #821 ShortestDistanceToACharacter. Algorithm,알고리즘,LeetCode,Codefights,CodeSignal,코드파이트,코드시그널,예제,문제해결능력,example,c++,java,재귀,recursive,datastructure,techinterview,coding,코딩인터뷰,기술면접,연결리스트
Runtime: 8 ms, faster than 97.03% of C++ online submissions for Shortest Distance to a Character.
Memory Usage: 8.9 MB, less than 100.00% of C++ online submissions for Shortest Distance to a Character.
LeetCode #821
Q.
Given a string S and a character C, return an array of integers representing the shortest distance from the character C in the string.
주어진 문자열 S 와 문자 C 가 있는데, 문자열의 문자들이 문자 C 까지의 가장 짧은 거리값을 나타내는 정수 배열을 반환해라.
Example 1:
Input: S = "loveleetcode", C = 'e'
Output: [3, 2, 1, 0, 1, 0, 0, 1, 2, 2, 1, 0]
Note:
- S string length is in [1, 10000].
- C is a single character, and guaranteed to be in string S.
- All letters in S and C are lowercase.
Process
// Process
//1. Input string S and char C
//2. Find char C indexes and make cIndexVector
//3. Iterate S (i)
// 3.1. Iterate cIndedVector (j)
// 3.1.1. Get shortestDistance from C, of S[i]
// 3.1.2. Put shortDistance to the resultVector
//4. Return resultVector
// 처리과정
//1. 문자열 S, 문자 C 입력받는다.
//2. 문자열 S 에서의 문자 C 가 있는 인덱스를 구해둔다. (cIndexVector)
//3. 문자열 S 반복한다. (i)
// 3.1. cIndexVector 반복한다. (j)
// 3.1.1. S[i] 에서 문자 C 까지 가장 짧은 거리를 구한다.
// 3.1.2. 가장 짧은 거리를 resultVector 에 넣는다.
//4. resultVector 반환한다.
Code.. lemme see example code!!!
코드.. 예제코드를 보자!!!
class Solution {
public:
vector<int> shortestToChar(string S, char C) {
vector<int> resultVector;
vector<int> cIndexVector;
// 2.
for (int i = 0; i < S.length(); ++i) {
if (S[i] == C) {
cIndexVector.push_back(i);
}
}
// 3.
for (int i = 0; i < S.length(); ++i) {
int shortDistance = 10000;
for (int j = 0; j < cIndexVector.size(); ++j) {
int distance = abs(i - cIndexVector[j]);
if (distance < shortDistance) {
shortDistance = distance;
}
}
resultVector.push_back(shortDistance);
}
return resultVector;
}
};
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