LeetCode #896 MonotonicArray. Algorithm,알고리즘,LeetCode,Codefights,CodeSignal,코드파이트,코드시그널,예제,문제해결능력,example,c++,java,재귀,recursive,datastructure,techinterview,coding,코딩인터뷰,기술면접,연결리스트
Idk why it has best performance
퍼포먼스 왜 잘나오는건지 모르겠음
Runtime: 76 ms, faster than 94.39% of C++ online submissions for Monotonic Array.
Memory Usage: 14 MB, less than 100.00% of C++ online submissions for Monotonic Array.
LeetCode #896
Q.
An array is monotonic if it is either monotone increasing or monotone decreasing.
An array A is monotone increasing if for all i <= j, A[i] <= A[j]. An array A is monotone decreasing if for all i <= j, A[i] >= A[j].
Return true if and only if the given array A is monotonic.
만약 배열이 쭉 오름차순이거나 내림차순이면, 그 배열은 단조증가, 단조감소 한다고 한다.
단조증가는 i<=j, A[i] <=A[j] 이고, 단조감소는 i<=j, A[i] >= A[j] 이다.
주어진 배열이 단조배열인지 확인해봐라.
Example 1:
Input: [1,2,2,3]
Output: true
Example 2:
Input: [6,5,4,4]
Output: true
Example 3:
Input: [1,3,2]
Output: false
Example 4:
Input: [1,2,4,5]
Output: true
Example 5:
Input: [1,1,1]
Output: true
Note:
- 1 <= A.length <= 50000
- -100000 <= A[i] <= 100000
Process
// Process
//1. Input vector A
//2. Decide flag if it's increase or decrease monotonic vector
//3. Iterate from 0 to the end - 1 (i)
// 3.1. Check if i'th and i+1'th values are fit to flag
// 3.1.1. If not -> it's false result
//4. Return result;
// 처리과정
//1. 배열 입력받는다
//2. 배열이 오름차순인지 내림차순인지 확인해서 flag 만들어둔다.
//3. 시작부터 끝-1 까지 반복한다.
// 3.1. 값과 바로뒤의 값이 flag 에 부합하는지 확인해서
// 3.1.1. 맞지 않으면 result 는 false
//4. 결과 반환한다.
Code.. lemme see example code!!!
코드.. 예제코드를 보자!!!
class Solution {
public:
bool isMonotonic(vector<int>& A) {
bool result = true;
bool isIncrease;
// if (A.size() < 1)
// return false;
if (A[0] <= A[A.size()-1])
isIncrease = true;
else
isIncrease = false;
for (int i = 0; result && i < A.size()-1; ++i) {
if (A[i] == A[i+1]) {
}
else if (A[i] > A[i + 1] && isIncrease) {
result = false;
}
else if (A[i] < A[i + 1] && !isIncrease) {
result = false;
}
}
return result;
}
};
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