LeetCode #344 ReverseString. Algorithm,알고리즘,LeetCode,Codefights,CodeSignal,코드파이트,코드시그널,예제,문제해결능력,example,c++,java,재귀,recursive,datastructure,techinterview,coding,코딩인터뷰,기술면접,연결리스트
Runtime: 36 ms, faster than 99.50% of C++ online submissions for Reverse String.
Memory Usage: 15.2 MB, less than 95.12% of C++ online submissions for Reverse String.
LeetCode #344
Q.
Write a function that reverses a string. The input string is given as an array of characters char[].
Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.
You may assume all the characters consist of printable ascii characters.
문자열을 뒤집는 함수를 만들어라. 들어오는 문자열은 char[] 배열이다.
새로 추가로 다른 배열을 할당하지 말고, 들어온 배열을 조작해서 O(1) 으로 끝내야 한다.
모든 문자들은 출력가능한 아스키 문자로 되어있다.
Example 1:
Input: ["h","e","l","l","o"]
Output: ["o","l","l","e","h"]
Example 2:
Input: ["H","a","n","n","a","h"]
Output: ["h","a","n","n","a","H"]
Process
// Process
//1. Input array
//2. Make char buffer
//3. Iterate array
// 3.1. Swap chars
//4. Return array
// 처리과정
//1. 배열 입력받는다
//2. char 버퍼를 만들어둔다.
//3. 배열 전체 반복한다.
// 3.1. 문자들 자리 교체한다.
//4. 배열 반환한다.
Code.. lemme see example code!!!
코드.. 예제코드를 보자!!!
class Solution {
public:
void reverseString(vector<char>& s) {
if (s.size() > 0) {
char charBuffer;
for (int i = 0; i < s.size() / 2; ++i) {
charBuffer = s[i];
s[i] = s[s.size()-1-i];
s[s.size()-1-i] = charBuffer;
}
// vector<char> newVec;
// for (int i = s.size() - 1; i >= 0; --i) {
// newVec.push_back(s[i]);
// }
// s = newVec;
}
}
};
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