LeetCode #191 NumberOf1Bits. Algorithm,알고리즘,LeetCode,Codefights,CodeSignal,코드파이트,코드시그널,예제,문제해결능력,example,c++,java,재귀,recursive,datastructure,techinterview,coding,코딩인터뷰,기술면접,연결리스트
Runtime: 0 ms, faster than 100.00% of C++ online submissions for Number of 1 Bits.
Memory Usage: 8.1 MB, less than 92.68% of C++ online submissions for Number of 1 Bits.
LeetCode #191
Q.
Write a function that takes an unsigned integer and return the number of '1' bits it has (also known as the Hamming weight).
unsigned 정수 를 받아서, 갖고있는 bit 중 1 인 수의 개수를 반환해라 (a.k.a. 해밍웨이트)
Example 1:
Input: 00000000000000000000000000001011
Output: 3
Explanation: The input binary string 00000000000000000000000000001011 has a total of three '1' bits.
Example 2:
Input: 00000000000000000000000010000000
Output: 1
Explanation: The input binary string 00000000000000000000000010000000 has a total of one '1' bit.
Example 3:
Input: 11111111111111111111111111111101
Output: 31
Explanation: The input binary string 11111111111111111111111111111101 has a total of thirty one '1' bits.
Note:
- Note that in some languages such as Java, there is no unsigned integer type. In this case, the input will be given as signed integer type and should not affect your implementation, as the internal binary representation of the integer is the same whether it is signed or unsigned.
- In Java, the compiler represents the signed integers using 2's complement notation. Therefore, in Example 3 above the input represents the signed integer -3.
Process
// Process
//1. Input unsigned32int n
//2. Make n to bitset
//3. Count of 1 in bit
//4. Return count
// 처리과정
//1. unsigned int n 입력받는다.
//2. 비트셋으로 바꾼다.
//3. 비트셋 중 1 의 개수를 센다.
//4. 개수 반환한다.
Code.. lemme see example code!!!
코드.. 예제코드를 보자!!!
class Solution {
public:
int hammingWeight(uint32_t n) {
int count = 0;
bitset<32> xBit(n);
for (int i = 0; i < xBit.size(); ++i) {
if (xBit[i] == 1)
++count;
}
return count;
}
};
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