LeetCode #169 MajorityElement. Algorithm,알고리즘,LeetCode,Codefights,CodeSignal,코드파이트,코드시그널,예제,문제해결능력,example,c++,java,재귀,recursive,datastructure,techinterview,coding,코딩인터뷰,기술면접
퍼포먼스 어정쩡할 느낌이었는데 98% 나옴. std::find 포스팅 하자마자 find 쓰는 문제 풀어서 상쾌함
I thought it's performance would not that good, but it's 98%. Also I'm proud of me, cuz I posted std::find function right before it and I solved this using that function.
2019/04/02 - [Programming/C++] - How to find if vector contains specific value or not in C++, 씨쁠쁠 stl 벡터에 특정 값이 이미 있는지 확인하는 방법
How to find if vector contains specific value or not in C++, 씨쁠쁠 stl 벡터에 특정 값이 이미 있는지 확인하는 방법
How to find if vector contains specific value or not in C++, 씨쁠쁠 stl 벡터에 특정 값이 이미 있는지 확인하는 방법 std::find 함수를 써서 vector 의 시작부터 끝까지 확인해서 확인한다. We can check if..
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LeetCode #169
Q.
Given an array of size n, find the majority element. The majority element is the element that appears
more than ⌊ n/2 ⌋ times.
n 사이즈의 주어진 배열에서, 주요인자를 찾아라. 주요인자는 n / 2 회 넘게 나타나는 것이다.
단, 빈 배열은 없고, 주요인자는 항상 있다.
e.g.
Example 1:
Input: [3,2,3]
Process
// Process
// 처리과정
//1. 정수배열을 입력받는다.
//2. 시작부터 끝까지 반복한다.
// 2.1. 이미 나왔던 수인지 확인해서
// 2.1.1. 안나온 거면
-> 나왔던 수 배열에 넣는다.
-> n/2 회 이상 나오는 주요인자인지 확인한다.
//3. 주요인자 반환한다.
Code.. lemme see example code!!!
코드.. 예제코드를 보자!!!
class Solution {
public:
int majorityElement(vector<int>& nums) {
int majorityInt = 0;
bool isDone = false;
std::vector<int> previousInt;
for (int i = 0; !isDone && i < nums.size(); ++i) {
if (std::find(previousInt.begin(), previousInt.end(), nums[i]) != previousInt.end()) {
}
else {
int count = 1;
for (int j = i + 1; j < nums.size(); ++j) {
if (nums[i] == nums[j])
++count;
}
if (count > nums.size() / 2) {
majorityInt = nums[i];
isDone = true;
}
previousInt.push_back(nums[i]);
}
}
return majorityInt;
}
};
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