LeetCode #290 WordPattern. Algorithm,알고리즘,LeetCode,Codefights,CodeSignal,코드파이트,코드시그널,예제,문제해결능력,example,c++,java,재귀,recursive,datastructure,techinterview,coding,코딩인터뷰,기술면접
두시간은 걸린 듯..
istringstream 과 iterator 이용해서 string 쪼개는 것 포스팅도 하고.. pattern 에서 중복되는 반복 없게끔 하려다가 끝에가서 막혀서 중복되게 그냥 풀었는데 퍼포먼스 100% 나옴....
I spent almost 2 hours...
Posted how to split string using istringstream and iterator.. I wanted to make code without duplicate iteration in pattern chars, but at the last i stucked, so i just solved with duplicated iter. Wtf.. performance 100%.. ?
How to split
문자열 쪼개는 방법
2019/02/15 - [Programming/C++] - Simplest way to split string in c++, Split string using stream/iterator, 스페이스 기준 문자열/단어 나누기, c++, java, stl, std
LeetCode #290
Q.
Given a pattern and a string str, find if str follows the same pattern.
Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in str.
패턴과 문자열이 주어지고, 패턴에 맞는 문자열인지 확인해봐라
전부 맞아야한다. 비어있지 않은 문자열과, pattern 의 캐릭터들이 딱 맞게 합쳐져야 한다.
e.g.
Example 1:
Input: pattern = "abba", str = "dog cat cat dog"
Output: true
Example 2:
Input:pattern = "abba", str = "dog cat cat fish"
Output: false
Example 3:
Input: pattern = "aaaa", str = "dog cat cat dog"
Output: false
Example 4:
Input: pattern = "abba", str = "dog dog dog dog"
Output: false
Process
// Process
//1. Input pattern and string
//2. Split str to each words
//3. Compare with pattern chars
//4. Return result
// splitSentence
//1. Input sentence string
//2. Split using istream and iterator
//3. Return result words
// 처리과정
//1. 패턴과 문자열을 입력받는다.
//2. 문자열을 각 단어로 끊어낸다.
//3. 패턴과 문자들을 비교한다.
//4. 결과를 반환한다.
// splitSentence
//1. 문장을 입력받는다.
//2. istream 과 iterator 를 이용해서 space 단위로 끊어낸다.
//3. 결과 문자들을 벡터로 반환한다.
Code.. lemme see example code!!!
코드.. 예제코드를 보자!!!
#include <string>
#include <iostream>
#include <vector>
#include <iterator>
#include <sstream>
using namespace std;
class Solution {
public:
private:
vector<string> splitSentence(string sentence) {
istringstream iss(sentence);
vector<string> result((istream_iterator<string>(iss)), istream_iterator<string>());
return result;
}
public:
bool wordPattern(string pattern, string str) {
vector<string> words = this->splitSentence(str);
if (words.size() != pattern.size())
return false;
for (int i = 0; i < pattern.size(); ++i)
{
for (int j = i + 1; j < pattern.size(); ++j)
{
if (pattern[i] == pattern[j])
{
if (words[i] != words[j])
return false;
}
else
{
if (words[i] == words[j])
return false;
}
}
}
return true;
}
};
int main(int argc, char *argv[]) {
Solution sln;
sln.wordPattern("jquery", "jquery");
return 0;
}
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