LeetCode #283 MoveZeroes. Algorithm,알고리즘,LeetCode,Codefights,CodeSignal,코드파이트,코드시그널,예제,문제해결능력,example,c++,java,재귀,recursive,datastructure,techinterview,coding,코딩인터뷰,기술면접
한 5분정도 걸렸고, 퍼포먼스는 중하, 메모리는 상
It was easy, 5 min, mid-low performance, best memory.
For the performance, I should've used swap() function in stl, maybe.
퍼포먼스를 더 내려면 erase / push 말고 swap 을 쓰면 될 것 같다.
LeetCode #283
Q.
Given an array nums, write a function to move all 0's to the end of it while maintaining the relative order of the non-zero elements.
숫자 배열이 주어지고, 모든 0 을 제일 뒤로 몰아넣어라.
e.g.
Example:
Input: [0,1,0,3,12]
Output: [1,3,12,0,0]
Note:
You must do this in-place without making a copy of the array.
Minimize the total number of operations.
추가로 :
배열 복사 없이 해야하고, 함수 사용을 최소화 해봐라.
Process
// Process
//1. input num vector
//2. Iterate from begin to the end - zeroCount
// 2.1. Check if it's 0
// 2.1.1. If so -> erase and push to back
//3. Return vector (pointer)
// 처리과정
//1. 배열을 입력받는다.
//2. 시작부터 끝-zeroCount 까지 반복한다.
// 2.1. 0 인지 확인해서
// 2.1.1. 0 이면 지우고 제일 뒤로 보낸다.
//3. 배열 반환한다. (포인터)
Code.. lemme see example code!!!
코드.. 예제코드를 보자!!!
#include <vector>
using namespace std;
class Solution {
public:
void moveZeroes(vector<int>& nums) {
int zeroCount = 0;
for (int i = 0; i < nums.size() - zeroCount; ++i)
{
if (nums[i] == 0)
{
nums.erase(nums.begin() + i);
nums.push_back(0);
++zeroCount;
--i;
}
}
}
};
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