LeetCode #83 RemoveDuplicatesFromSortedList. Algorithm,알고리즘,LeetCode,Codefights,CodeSignal,코드파이트,코드시그널,예제,문제해결능력,example,c++,java,재귀,recursive,datastructure,techinterview,coding,코딩인터뷰,기술면접
노드 구조체를 포인터 써서 이동함. 퍼포먼스 100%
Move using node struct. 100% performance..
LeetCode #83
Q.
Given a sorted linked list, delete all duplicates such that each element appear only once.
주어진 정렬된 연결리스트에서, 중복되는 인자들을 다 지워라
e.g.
Example 1:
Input: 1->1->2
Output: 1->2
Example 2:
Input: 1->1->2->3->3
Output: 1->2->3
Process
// Process
//1. Input head node
//2. Iterate till the next is null
// 2.1. Check if val and nextVal are the same or not
// 2.1.1. If so -> pass to next of the next
// 2.1.2. If not -> pass to the next
//3. Return head node
// 처리과정
//1. 헤드노드를 입력받는다.
//2. 다음 노드가 없을때까지 반복한다.
// 2.1. 현재노드의 값과 다음노드 값을 비교해서
// 2.1.1. 같으면 -> 다음 노드의 다음 값으로 넘어간다.
// 2.1.2. 다르면 -> 다음 노드로 넘어간다.
//3. 헤드노드 반환한다.
Code.. lemme see example code!!!
코드.. 예제코드를 보자!!!
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* deleteDuplicates(ListNode* head) {
if (head != 0) {
ListNode* tempNode = head;
while (tempNode->next != 0) {
if (tempNode->val == tempNode->next->val) {
tempNode->next = tempNode->next->next;
} else {
tempNode = tempNode->next;
}
}
}
return head;
}
};
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