LeetCode #118 Pascal'sTriangle. Algorithm,알고리즘,LeetCode,Codefights,CodeSignal,코드파이트,코드시그널,예제,문제해결능력,example,c++,java,재귀,recursive,datastructure,techinterview,coding,코딩인터뷰,기술면접
LeetCode #118
Q.
Given a non-negative integer numRows, generate the first numRows of Pascal's triangle.
e.g.
Example:
Input: 5
Output: [ [1],
[1,1],
[1,2,1],
[1,3,3,1],
[1,4,6,4,1] ]
Process
// Process
// 처리과정
//1. numRows 입력받는다.
//2. 시작부터 numRows 까지 반복한다.
// 2.1. 해당 층 vector 를 만든다.
// 2.2. 해당 층 vector 를 채운다.
// 2.3. resultVector 에 채워넣는다.
//3. resultVector를 반환한다.
Code.. lemme see example code!!!
코드.. 예제코드를 보자!!!
#include <vector>
#include <iostream>
using namespace std;
// Process
//1. Input numRows
//2. Iterate from 1 to numRows
// 2.1. Make vector using iter index
// 2.2. Fill the vector
// 2.3. Put the vector to resultVector
//3. Return resultVector
class Solution {
public:
vector<vector<int>> generate(int numRows) {
vector<vector<int>> resultVector;
if (numRows > 0) {
vector<int> tempFirst = { 1 };
resultVector.push_back(tempFirst);
for (int i = 1; i < numRows; ++i) {
vector<int> tempVector;
tempVector.push_back(1);
for (int j = 0; j < i-1; ++j) {
int sum = resultVector.at(i - 1).at(j) + resultVector.at(i - 1).at(j + 1);
tempVector.push_back(sum);
}
tempVector.push_back(1);
resultVector.push_back(tempVector);
}
}
return resultVector;
}
};
int main(int argc, char *argv[]) {
Solution sln;
vector<vector<int>> result = sln.generate(3);
for (int i = 0; i < result.size(); ++i) {
for (int j = 0; j < result.at(i).size(); ++j) {
cout << result.at(i).at(j);
}
cout << endl;
}
}
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