LeetCode #88 MergeSortedAray. Algorithm,알고리즘,LeetCode,Codefights,CodeSignal,코드파이트,코드시그널,예제,문제해결능력,example,c++,java,재귀,recursive,datastructure,techinterview,coding,코딩인터뷰,기술면접
어제 했던 병합정렬 쉬운 버전..
Easy version of the merge sort what i did yesterday..
LeetCode #88
Q.
Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
주어진 두개의 정렬된 정수 배열에서, 두개를 합쳐서 한개의 정렬된 배열을 만들어라
Note:
- The number of elements initialized in nums1 and nums2 are m and n respectively.
- You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2.
각 요소들은 각각 m, n 개 있다.
nums1 배열은 두개 합친 사이즈만큼 널널하다. (하나로 합치라는 듯?)
e.g.
Example:
Input: nums1 = [1,2,3,0,0,0], m = 3 nums2 = [2,5,6], n = 3
Output: [1,2,2,3,5,6]
Process
// Process
//1. input num vectors
//2. Iterate till both are remaining
// 2.1. Compare and fill the resultVector
//3. Fill the resultVector using remained vector
//4. Return resultVector
// 처리과정
//1. 정렬된 두 배열 입력받는다.
//2. 두 배열 남아있을때까지 반복한다.
// 2.1. 비교해서 resultVector 채워넣는다.
//3. 남은 배열 resultVector 에 채워넣는다.
//4. resultVector 반환한다.
Code.. lemme see example code!!!
코드.. 예제코드를 보자!!!
class Solution {
public:
void merge(vector<int>& nums1, int m, vector<int>& nums2, int n) {
int nums1Index = 0;
int nums2Index = 0;
vector<int> resultVector;
while (nums1Index < m && nums2Index < n) {
if (nums1[nums1Index] < nums2[nums2Index]) {
resultVector.push_back(nums1[nums1Index++]);
} else {
resultVector.push_back(nums2[nums2Index++]);
}
}
while (nums1Index < m) {
resultVector.push_back(nums1[nums1Index++]);
}
while (nums2Index < n) {
resultVector.push_back(nums2[nums2Index++]);
}
nums1 = resultVector;
}
};
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