LeetCode #104 MaximumDepthOfBinaryTree. Algorithm,알고리즘,LeetCode,Codefights,CodeSignal,코드파이트,코드시그널,예제,문제해결능력,example,c++,java,재귀,recursive,datastructure,techinterview,coding,코딩인터뷰,기술면접
Nice performance
LeetCode #104
Q.
Given a binary tree, find its maximum depth.
The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
Note: A leaf is a node with no children.
주어진 바이너리 트리에서, 최대 깊이를 찾아라.
최대 깊이는 루트노드로부터 가장 멀리 있는 노드의 층수이다.
e.g.
Example:
Given binary tree [3,9,20,null,null,15,7],
3
/ |
9 20
/ |
15 7
return its depth = 3.
Process
// Process
//1. Input root node
//2. Make maxDepth, depth
//3. Call recursiveCheckDepth
//4. Return maxDepth
// recursiveCheckDepth
//1. Input node, maxDepth, depth
//2. Get it's depth
//3. Compare depth with maximum depth, and do something
//4. Call recursive function using left and right
// 처리과정
//1. 루트노드 입력받는다.
//2. maxDepth, depth 만든다.
//3. recursiveCheckDepth 호출한다.
//4. maxDepth 반환한다.
// recursiveCheckDepth
//1. node, maxDepth, depth 입력 받는다.
//2. 층수를 구한다.
//3. 층수와 최대층수 비교해서 값 넣는다.
//4. 재귀함수 호출한다.
Code.. lemme see example code!!!
코드.. 예제코드를 보자!!!
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
int maxDepth(TreeNode* root) {
int maxDepth = 0;
int depth = 0;
recursiveCheckDepth(root, &maxDepth, &depth);
return maxDepth;
}
private:
void recursiveCheckDepth(TreeNode* node, int *maxDepth, int *depth) {
if (node != 0) {
++*depth;
if (*depth > *maxDepth)
*maxDepth = *depth;
if (node->left != 0)
recursiveCheckDepth(node->left, maxDepth, depth);
if (node->right != 0)
recursiveCheckDepth(node->right, maxDepth, depth);
--*depth;
}
}
};
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