LeetCode #965 UnivaluedBinaryTree. Algorithm,알고리즘,LeetCode,Codefights,CodeSignal,코드파이트,코드시그널,예제,문제해결능력,example,c++,java,재귀,recursive,datastructure,techinterview,coding,코딩인터뷰,기술면접,연결리스트
Performance 96%
Memory 60%
LeetCode #965
Q.
A binary tree is univalued if every node in the tree has the same value.
Return true if and only if the given tree is univalued.
이진트리의 모든 노드 값이 같은 값이면 univalued 라고 한다. univalued 가 true 인지 false 인지 리턴하는 함수를 만들어라.
e.g.
Example 1:
Input: [1,1,1,1,1,null,1]
Output: true
Example 2:
Input: [2,2,2,5,2]
Output: false
Note:
The number of nodes in the given tree will be in the range [1, 100].
Each node's value will be an integer in the range [0, 99].
Process
// Process
// 처리과정
//1. 노드 입력받는다.
//2. 노드가 null 이 아니면
// 2.1. 노드값과 왼쪽노드의값을 비교해서 같으면
// 2.1.1. 왼쪽 노드 넣어서 재귀호출 한다.
// 2.2. 노드값과 오른쪽노드 값을 비교해서 같으면
// 2.2.1. 오른쪽 노드 넣어서 재귀호출 한다.
//3. 결과 반환한다.
Code.. lemme see example code!!!
코드.. 예제코드를 보자!!!
class Solution {
public:
bool isUnivalTree(TreeNode* root) {
// * 1 2
bool answer = true;
if (root != 0) {
if (root->left != 0 && root->val != root->left->val) {
return false;
}
else {
answer = isUnivalTree(root->left);
}
if (answer) {
if (root->right != 0 && root->val != root->right->val) {
return false;
}
else {
answer = isUnivalTree(root->right);
}
}
}
return answer;
}
};
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