LeetCode #509 FibonacciNumber. Algorithm,알고리즘,LeetCode,Codefights,CodeSignal,코드파이트,코드시그널,예제,문제해결능력,example,c++,java,재귀,recursive,datastructure,techinterview,coding,코딩인터뷰,기술면접,연결리스트
Performance 40%
Memory 30%
LeetCode #509
Q.
The Fibonacci numbers, commonly denoted F(n) form a sequence, called the Fibonacci sequence, such that each number is the sum of the two preceding ones, starting from 0 and 1.
That is,F(0) = 0, F(1) = 1 F(N) = F(N - 1) + F(N - 2), for N > 1.
Given N, calculate F(N).
Example 1:
Input: 2
Output: 1
Explanation: F(2) = F(1) + F(0) = 1 + 0 = 1.
Example 2:
Input: 3
Output: 2
Explanation: F(3) = F(2) + F(1) = 1 + 1 = 2.
Example 3:
Input: 4
Output: 3
Explanation: F(4) = F(3) + F(2) = 2 + 1 = 3.
Note:
0 ≤ N ≤ 30.
Process
// Process
//1. Input integer N
//2. Call recursive function
//3. Return value
// recursiveFibonacci
//1. Input integer
//2. If input integer is 0 or 1
// 2.1. Return input integer
//3. If input integer is bigger than 1
// 3.1. Call recursiveFibonacci( n - 1 ) and add to sum
// 3.2. Call recursiveFIbonacci( n - 2 ) and add to sum
//4. Return sum
// 처리과정
//1. 정수 N 입력받는다.
//2. 재귀 호출한다.
//3. 값 반환한다.
// recursiveFibonacci
//1. 정수 입력받는다.
//2. 입력받은 수가 1이나 0 이면
// 2.1. 입력받은 수 그대로 반환한다.
//3. 입력받은 수가 1보다 크면
// 3.1. recursiveFibonacci( n - 1 ) 해서 sum 에 더한다.
// 3.2. recursiveFibonacci( n - 2 ) 해서 sum 에 더한다.
//4. sum 반환한다.
Code.. lemme see example code!!!
코드.. 예제코드를 보자!!!
class Solution {
public:
int fib(int N) {
return recursiveFib(N);
}
private:
int recursiveFib(int n) {
int sum = 0;
if (n == 0 || n == 1)
return n;
if (n > 1) {
sum += recursiveFib(n - 2);
sum += recursiveFib(n - 1);
}
return sum;
}
};
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