LeetCode #268 MissingNumber. Algorithm,알고리즘,LeetCode,Codefights,CodeSignal,코드파이트,코드시그널,예제,문제해결능력,example,c++,java,재귀,recursive,datastructure,techinterview,coding,코딩인터뷰,기술면접,연결리스트
Runtime: 24 ms, faster than 81.41% of C++ online submissions for Missing Number.
Memory Usage: 11.1 MB, less than 5.14% of C++ online submissions for Missing Number.
LeetCode #260
Q.
Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array.
0부터 n까지의 숫자가 있는 배열에서, 배열에 빠져있는 숫자 한개를 찾아라.
Example 1:
Input: [3,0,1]
Output: 2
Example 2:
Input: [9,6,4,2,3,5,7,0,1]
Output: 8
Note:
Your algorithm should run in linear runtime complexity. Could you implement it using only constant extra space complexity?
Process
// Process
//1. Input array
//2.
// 처리과정
//1. 배열 입력받는다
//2.
Code.. lemme see example code!!!
코드.. 예제코드를 보자!!!
class Solution {
public:
int missingNumber(vector<int>& nums) {
vector<int> dynamicVec;
for (int i = 0; i <= nums.size(); ++i) {
dynamicVec.push_back(0);
}
for (int i = 0; i < nums.size(); ++i)
++dynamicVec[nums[i]];
for (int i = 0; i < dynamicVec.size(); ++i)
if (dynamicVec[i] == 0)
return i;
return 0;
}
};
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