LeetCode #171 ExcelSheetColumnNumber. Algorithm,알고리즘,LeetCode,Codefights,CodeSignal,코드파이트,코드시그널,예제,문제해결능력,example,c++,java,재귀,recursive,datastructure,techinterview,coding,코딩인터뷰,기술면접
퍼포먼스는 상당히 잘나왔고, 메모리는 안좋음
Performance is best, memory is not good
LeetCode #171
Q.
Given a column title as appear in an Excel sheet, return its corresponding column number.
엑셀시트에 나타나는 컬럼 이름을 입력 받고, 입력한 숫자에 상응하는 수를 반환해라
e.g.
A -> 1
B -> 2
C -> 3
...
Z -> 26
AA -> 27
AB -> 28
...
Example 1:
Input: "A"
Output: 1
Example 2:
Input: "AB"
Output: 28
Example 3:
Input: "ZY"
Output: 701
Process
// Process
//1. Input column string
//2. Iterate from begin to the end
// 2.1. Add that alphabet number and pow(26 and index-1)
//3. Return answerString
// 처리과정
//1. 엑셀시트 컬럼 문자를 입력받는다.
//2. 시작부터 끝까지 반복한다.
// 2.1. 해당 알파벳 숫자와 26의 인덱스 제곱을 결과값에 더한다.
//3. 결과값을 반환한다.
Code.. lemme see example code!!!
코드.. 예제코드를 보자!!!
#include <iostream>
#include <string>
using namespace std;
class Solution {
public:
int titleToNumber(string s) {
int answerNumber = 0;
for (int i = 0; i < s.size(); ++i)
{
answerNumber += ((s[i] - 64) * pow(26, s.size() - 1 - i));
}
return answerNumber;
}
};
int main(int argc, char *argv[]) {
//cout << "Hello" << endl;
string inputString = "AAB";
Solution sln;
cout << sln.titleToNumber(inputString) << endl;
}
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