LeetCode #1137 N-thTribonacciNumber. Algorithm,알고리즘,LeetCode,Codefights,CodeSignal,코드파이트,코드시그널,예제,그래프,Graph,example,c++,java,재귀,recursive,datastructure,techinterview,coding,코딩인터뷰,기술면접
Runtime: 0 ms, faster than 100.00% of C++ online submissions for N-th Tribonacci Number.
Memory Usage: 8.1 MB, less than 100.00% of C++ online submissions for N-th Tribonacci Number.
LeetCode #1137
Q.
The Tribonacci sequence Tn is defined as follows:
T0 = 0, T1 = 1, T2 = 1, and Tn+3 = Tn + Tn+1 + Tn+2 for n >= 0.
Given n, return the value of Tn.
트라이보나치 행렬 Tn 은 다음과 같이 정의된다:
T0 = 0, T1 = 1, T2 = 1, 그리고 Tn+3 = Tn + Tn+1 + Tn+2 이고 n>=0 이다. (제일 뒤의 값은 앞 세개의 합과 같다는 것)
n 이 주어지면, Tn 의 값을 구하여라
Example 1:
Input: n = 4
Output: 4
Explanation: T_3 = 0 + 1 + 1 = 2 T_4 = 1 + 1 + 2 = 4
Example 2:
Input: n = 25
Output: 1389537
Constraints:
- 0 <= n <= 37
- The answer is guaranteed to fit within a 32-bit integer, ie. answer <= 2^31 - 1.
Process
// Process
//1. Input integer n
//2. Make tribonacci value sequence
//3. Return n-th value
// 처리과정
//1. 정수 n 입력받는다.
//2. 트라이보나치 행렬 값을 채워둔다.
//3. n 번째 값을 반환한다.
Code.. lemme see example code!!!
코드.. 예제코드를 보자!!!
class Solution {
public:
int tribonacci(int n) {
int result = 0;
//2.
int tribonacci[38] = { 0 };
tribonacci[0] = 0;
tribonacci[1] = 1;
tribonacci[2] = 1;
for (int i = 3; i < 38; ++i) {
tribonacci[i] = tribonacci[i-3] + tribonacci[i-2] + tribonacci[i-1];
}
//3.
return tribonacci[n];
}
};
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