LeetCode #181 EmployeesEarningMoreTheirManagers. Algorithm,알고리즘,LeetCode,Codefights,CodeSignal,코드파이트,코드시그널,예제,그래프,Graph,example,c++,java,재귀,recursive,datastructure,techinterview,coding,코딩인터뷰,기술면접, 데이터베이스, sql, query, 쿼리
Runtime: 306 ms, faster than 73.60% of MySQL online submissions for Employees Earning More Than Their Managers.
Memory Usage: 0B, less than 100.00% of MySQL online submissions for Employees Earning More Than Their Managers.
LeetCode #181
Q.
SQL Schema
The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id.
Employee 테이블이 있고, 모든 employee 에는 매니저들도 포함이 된다. 모든 직원은 ID 가 있고, 컬럼 중에는 managerID 도 있다.
+----+-------+--------+-----------+
| Id | Name | Salary | ManagerId |
+----+-------+--------+-----------+
| 1 | Joe | 70000 | 3 |
| 2 | Henry| 80000 | 4 |
| 3 | Sam | 60000 | NULL |
| 4 | Max | 90000 | NULL |
+----+-------+--------+-----------+
Given the Employee table, write a SQL query that finds out employees who earn more than their managers. For the above table, Joe is the only employee who earns more than his manager.
Employee 테이블이 주어지고, 직원 중에서 해당 매니저보다 돈을 더 버는 직원을 찾는 SQL 쿼리문을 작성해라. 위의 테이블에서, Joe 가 그의 매니저보다 돈을 더버는 유일한 직원이다.
+----------+
| Employee |
+----------+
| Joe |
+----------+
Process
// Process
//1.
// 처리과정
//1. 'Employee' 라는 검색테이블명으로 a 에서 Name을 찾는데
//2. a 라는 이름으로 Employee 를 찾고, b 라는 이름으로 Employee 를 찾는다.
//3. 그 중에서, a 검색결과의 Salary 가 b 검색결과 Salary 보다 크면서,
// 3.1. a 의 ManagerId 가 b 의 Id 인 것의 Name 을 찾는 것이다.
Code.. lemme see example code!!!
코드.. 예제코드를 보자!!!
# Write your MySQL query statement below
SELECT a.Name AS 'Employee'
FROM Employee AS a, Employee AS b
WHERE a.Salary > b.Salary
AND a.ManagerId = b.Id;
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