LeetCode #226 InvertBinaryTree. Algorithm,알고리즘,LeetCode,Codefights,CodeSignal,코드파이트,코드시그널,예제,문제해결능력,example,c++,java,재귀,recursive,datastructure,techinterview,coding,코딩인터뷰,기술면접,연결리스트
Runtime: 0 ms, faster than 100.00% of C++ online submissions for Invert Binary Tree.
Memory Usage: 9.8 MB, less than 5.45% of C++ online submissions for Invert Binary Tree.
LeetCode #226
Q.
Invert a binary tree.
이진트리를 뒤집어라.
Trivia:
This problem was inspired by this original tweet by Max Howell:
Google: 90% of our engineers use the software you wrote (Homebrew), but you can’t invert a binary tree on a whiteboard so f*** off.
퀴즈:
이 문제는 맥스 하웰이 쓴 이 트윗에서 영감을 얻었다.
- 구글 : 90%의 우리 엔지니어들은 니가 쓴 Homebrew 라는 소프트웨어를 사용하지만, 넌 바이너리 트리 뒤집는 코드도 화이트보드에서 못 쓴다 그니까 꺼져.
Process
//1. Input root node
//2. Check if it's null or not
// 2.1. If not -> call recursiveFunction
//3. Return resultRoot
// recursiveMakeTree
//1. Input originNode and resultNode
//2. Check if originNode->left is null or not
// 2.1. If not -> make new TreeNode to resultNode->right and call recursive function with originNode->left and resultNode->right
//3. Check if originNode->right is null or not
// 3.1. If not -> make new TreeNode to resultNode->left and call recursive function with originNode->right and resultNode->left
// 처리과정
//1. 루트노드 입력받는다.
//2. 눌포인트인지 확인해서
// 2.1. 눌이 아니면 -> 재귀함수 호출한다.
//3. 완성된 결과루트노드 반환한다.
// 재귀함수
//1. 기존트리노드와 결과트리노드를 입력받는다.
//2. 기존노드 왼쪽 노드가 비어있는지 아닌지 확인해서
// 2.1. 비어있지 않으면 -> 새 트리노드를 결과트리노드 오른쪽에 만들어주고, 기존노드 왼쪽과 결과노트 오른쪽을 넣어 재귀함수를 호출한다.
//3. 기존노드 오른쪽 노드가 비어있는지 아닌지 확인해서
// 3.1. 비어있지 않으면 -> 새 트리노드를 결과트리노드 왼쪽에 만들어주고, 기존노드 오른쪽과 결과노드 왼쪽을 넣어 재귀함수를 호출한다.
Code.. lemme see example code!!!
코드.. 예제코드를 보자!!!
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
TreeNode* invertTree(TreeNode* root) {
TreeNode* resultRoot = 0;
if (root != 0) {
resultRoot = new TreeNode(root->val);
recursiveInvertTree(root, resultRoot);
}
return resultRoot;
}
private:
void recursiveInvertTree(TreeNode* originNode, TreeNode* resultNode) {
if (originNode->left != 0) {
resultNode->right = new TreeNode(originNode->left->val);
recursiveInvertTree(originNode->left, resultNode->right);
}
if (originNode->right != 0) {
resultNode->left = new TreeNode(originNode->right->val);
recursiveInvertTree(originNode->right, resultNode->left);
}
}
};
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