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Algorithm/Leet Code

LeetCode #559 MaximumDepthOfN-aryTree. Algorithm,알고리즘,LeetCode,Codefights,CodeSignal,코드파이트,코드시그널,예제,문제해결능력,example,c++,java,재귀,recursive,datastructure,techinterview,coding,코딩인터뷰,기술면접

LeetCode #559 MaximumDepthOfN-aryTree. Algorithm,알고리즘,LeetCode,Codefights,CodeSignal,코드파이트,코드시그널,예제,문제해결능력,example,c++,java,재귀,recursive,datastructure,techinterview,coding,코딩인터뷰,기술면접



 트리는 풀 때마다 새로워서 재밌음, 퍼포먼스 88% 메모리 76% 둘다 괜춘


Tree structure is always new to me, so it's always interesting. Performance 88%, Memory 76%, kinda good.




LeetCode #559

Q.

Given a n-ary tree, find its maximum depth.

The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.

For example, given a 3-ary tree:

 

 

We should return its max depth, which is 3.


 주어진 n-ary 트리에서, 최대 깊이를 찾아라


최대 깊이는 루트노드로부터 가장 깊게 들어간 하위 노드의 층 숫자 이다.


예를 들면, 3-ary 트리에서 : (위의 그림)


최대깊이는 3 ( 5와 6 노드가 있는 깊이)



e.g. 

 위의 문제 설명에서 예시도 나와있다.

Example was in Q.


Process

// Process

//1. Input root node

//2. Check if root node is null or not

// 2.1. If not -> call diggingTree

//3. Return maxDepth

//4. Finish


// diggingTree

//1. Input node, maxDepth, depth

//2. If depth is bigger than maxDepth, then replace it.

//3. Iterate all leaf nodes

// 3.1. Call diggingTree (recursive)

//4. Finish



// 처리과정

//1. 루트 노드를 입력받는다.

//2. 루트노드가 null 인지 확인해서

// 2.1. 아니면 -> diggingTree 호출한다.

//3. max깊이 반환한다.

//4. 끝낸다.


// diggingTree

//1. 노드와, max깊이, 깊이를 입력받는다.

//2. 깊이가 max깊이보다 크면 치환한다.

//3. 하위 노드 전체를 반복한다.

// 3.1. diggingTree 호출한다 (재귀)

//4. 끝낸다.




Code.. lemme see example code!!!

코드.. 예제코드를 보자!!!





#include <vector>



using namespace std;


// Definition for a Node.

class Node {

public:

int val;

vector<Node*> children;


Node() {}


Node(int _val, vector<Node*> _children) {

val = _val;

children = _children;

}

};


class Solution {

private:

void diggingTree(Node* node, int* maxDepth, int depth) {

if (*maxDepth < ++depth)

*maxDepth = depth;

for (int i = 0; i < node->children.size(); ++i)

{

diggingTree(node->children.at(i), maxDepth, depth);

}

}

public:

int maxDepth(Node* root) {

int maxDepth = 0;

int depth = 0;


if (root != 0)

diggingTree(root, &maxDepth, depth);


return maxDepth;

}

};





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