e.g.
Example 1:
Input: "PPALLP"
Output: True
Example 2:
Input: "PPALLL"
Output: False
Process
// Process
//1. Input student attendance record string
//2. Iterate from begin to the end && countAbsent < 2 && countContinousLate < 3
// 2.1. Check if it's A
// 2.1.1. If so -> count absent
// 2.1.2. If else it's L
// 2.1.2.1. If so -> Check if it's continousLate
// 2.1.2.1.1. If so -> count continousLate
// 2.1.3. else
// 2.1.3.1. -> initialize continousLate
//3. Check any count is over the standard
//4. Return result
// 처리과정
//1. 학생 출석 기록 문자열을 입력받는다.
//2. 시작부터 끝까지 반복하고 && 결석횟수 < 2 && 연속지각횟수 < 3 이면 반복한다.
// 2.1. A 이면
// 2.1.1. 결석횟수 센다.
// 2.2. L 이면
// 2.2.1. 연속인지 확인해서
// 2.2.1.1. 연속이면 -> 연속횟수 센다.
// 2.2.1.2. 아니면 -> 연속으로 바꾼다.
// 2.3. 그 외이면
// 2.3.1. 연속지각 초기화한다.
//3. 각 횟수들이 기준치를 넘는지 확인해서 결과를 만든다.
//4. 결과 리턴한다.
Code.. lemme see example code!!!
코드.. 예제코드를 보자!!!
#include <string>
using namespace std;
class Solution {
public:
bool checkRecord(string s) {
int countAbsent = 0;
bool continousLate = false;
int countContinousLate = 1;
for (int i = 0; countAbsent < 2 && countContinousLate < 3
&& i < s.size(); ++i)
{
if (s[i] == 65)
{
++countAbsent;
continousLate = false;
countContinousLate = 1;
}
else if (s[i] == 76)
{
if (continousLate)
++countContinousLate;
else
continousLate = true;
}
else
{
continousLate = false;
countContinousLate = 1;
}
}
if (countAbsent > 1 || countContinousLate > 2)
return false;
return true;
}
};
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