LeetCode #832 FlippingAnImage. Algorithm,알고리즘,LeetCode,Codefights,CodeSignal,코드파이트,코드시그널,예제,문제해결능력,example,c++,java,재귀,recursive,datastructure,techinterview,coding,코딩인터뷰,기술면접,연결리스트
Runtime: 8 ms, faster than 98.29% of C++ online submissions for Flipping an Image.
Memory Usage: 9.3 MB, less than 62.39% of C++ online submissions for Flipping an Image.
LeetCode #832
Q.
Given a binary matrix A, we want to flip the image horizontally, then invert it, and return the resulting image.
To flip an image horizontally means that each row of the image is reversed. For example, flipping [1, 1, 0] horizontally results in [0, 1, 1].
To invert an image means that each 0 is replaced by 1, and each 1 is replaced by 0. For example, inverting [0, 1, 1] results in [1, 0, 0].
풀이과정이 곧 문제 내용임
주어진 이진수 매트릭스 A 가 있는데, 수평적으로 뒤집고, 역변환 하고 결과를 내고 싶다.
수평적으로 뒤집는다는 것은 이미지 행이 역순으로 간다는 것이다. 예를들면, [1,1,0] 은 [0,1,1] 이 된다.
역변환 한다는 것은 0 은 1로 1은 0으로 바꾸는 것이다. 예를들면, [0,1,1] 은 [1,0,0] 이 된다.
Example 1:
Input: [[1,1,0],[1,0,1],[0,0,0]]
Output: [[1,0,0],[0,1,0],[1,1,1]]
Explanation: First reverse each row: [[0,1,1],[1,0,1],[0,0,0]]. Then, invert the image: [[1,0,0],[0,1,0],[1,1,1]]
Example 2:
Input: [[1,1,0,0],[1,0,0,1],[0,1,1,1],[1,0,1,0]]
Output: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]
Explanation: First reverse each row: [[0,0,1,1],[1,0,0,1],[1,1,1,0],[0,1,0,1]]. Then invert the image: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]
Notes:
- 1 <= A.length = A[0].length <= 20
- 0 <= A[i][j] <= 1
Process
// Process
// 1. Input image 2d vector
// 2. Make reverse number vector
// 3. Make bitnot vector
// 4. Return vector
// 처리과정
//1. 이미지 2d 벡터 입력받는다.
//2. 각 row vector reverse 한다.
//3. 각 벡터 bitnot inverse 한다.
//4. 반환한다.
Code.. lemme see example code!!!
코드.. 예제코드를 보자!!!
class Solution {
public:
vector<vector<int>> flipAndInvertImage(vector<vector<int>>& A) {
for (int i = 0; i < A.size(); ++i) {
reverse(A[i].begin(), A[i].end());
}
for (int i = 0; i < A.size(); ++i) {
for (int j = 0; j < A[i].size(); ++j) {
A[i][j] = abs(A[i][j] - 1);
}
}
return A;
}
};
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